Laravel 5: How to modify Request values | How to "artificially" add values to Request array | How to dynamically add params to Request array

Laravel 5: How to modify Request values | How to "artificially" add values to Request array | How to dynamically add params to Request array. You can use the merge() method on the $request object. In spite of the methods name, it actually replaces any values associated with the member names specified by the keys of the parameter rather than concatenating their values or anything like that. 

A few times I encountered a situation – a store() or update() method with Request parameter, but I needed to add some additional value to the request before calling Eloquent functions. So how to do that? Apparently, pretty easy.

use Illuminate\Http\Request;

protected $request;

public function __construct(Request $request)
{
    $this->request = $request;

}

$this->request->merge(["custom" => "New Custom Value"]);

..

Laravel 5.X Forward To URL | Redirect To Route | Forward Request | Mock Request | Mock HTTP Request | Dynamic HTTP Request | Laravel Dispatch Request

Laravel 5.X Forward To URL | Redirect To Route | Forward Request | Mock Request | Mock HTTP Request | Dynamic HTTP Request.

It's easy to forward a request using Laravel Route. Forwarding do for you is URL will not change but response will change. The way it is working is that it will mock a request using Request::create(...) and dispatch using current Router.

<?php
namespace App\Http\Controllers;

use Illuminate\Routing\Router;
use App\Http\Controllers\Controller;
use Illuminate\Http\Request as HttpRequest;

class MyController extends Controller {
    public function __construct(HttpRequest $httpRequest, Router $router) {
        $this->middleware('auth', ['except' => ['action1', 'action2']]);

        $this->httpRequest = $httpRequest;
        $this->appRouter = $router;
    }

    //Route=my/need-forward (Create new request and dispatch)
    public function needForward() {
        //http://www.domain.com/my/need-forward
        $route_name = action("MyController@forwardHere");
        //http://www.domain.com/other-folder/my/need-forward
        $route_name = action("OtherFolder\\MyController@forwardHere");
        //http://www.domain.com/my/need-forward/100/Name%20Text?roll=303
        $route_name = action("MyController@forwardHere", ["id" => 100, "name" => "Name Text", "roll" => 303]);
        $request = HttpRequest::create($route_name, 'GET', array("param1" => "Param 1", "param2" => "Param 2"));
        return app()->handle($request);
    }

    //Route=my/need-forward (Forward same request to new route)
    public function needForward2() {
        $route_name = "my/forward-here";
        $request = HttpRequest::create($route_name);
        return  $this->appRouter->dispatch($request);
    }

    //Route=my/forward-here
    public function forwardHere() {
        echo "Browse [/my/need-forward] will send output of [/my/forward-here]";
    }
}

Get Current URL Using Laravel

Laravel is a strong php based framework today. We frequently coding on this platform. And who coded its important for him to know / get current working url sometimes. Its easy to get current url inside an Controller/Service class. Just need to use Request attribute to get desired output at Laravel. 

First need to import Request class to Controller/Service class:
use Illuminate\Http\Request;

And then need to pass Request as parameter as follows:
public function someAction(Request $request)

And finally use following method to get current full url:
$request->fullUrl();

You have different options when you use Laravel Request class as follows:

Get the request method
$request->method();

Get the root URL for the application
$request->root();

Get the URL (no query string) for the request
$request->url();

Get the full URL for the request
$request->fullUrl();

Get the current path info for the request
$request->path();

Determine if the request is the result of an AJAX call
$request->ajax(); 

There is another way around to get URL from Laravel Controller. 
At first you have to import following component:
use Illuminate\Routing\UrlGenerator;

Then need to initialize it on construct on controller as follows:
private $UrlGenerator;
public function __construct(UrlGenerator $UrlGenerator)
{
    $this->UrlGenerator = $UrlGenerator;
}

And then use below line of code get Laravel base URL:
$urlGenerator->to("/");

You can get all available method details of UrlGenerator from below link:
https://laravel.com/api/5.0/Illuminate/Routing/UrlGenerator.html
  

Pass old input/ get old input from view after Form Request validation in laravel

Sometimes we need to get old values in form to show them when error back to the same form, It is now well organized in Laravel. Consider the following situations:

1. Suppose you submitted a form with some values.
2. Found some errors and send back to the form again from Laravel controller to show the form again.
3. You have to show the values when he was here few moments ago (before submit the form)

$username = Request::old('username');

or in view:

{{ old('username') }}

How to get the current URL inside @if statement (blade) in Laravel

It is sometimes you need to control your view page(.blade.php) based on url visited by user. You can check if user visited by a Controller or Controller+Action both. It can be now done by Laravel very easily. Below is code snippet to do the tricks.

@if (Request::is('controller/*'))
    <!-- code block here -->
@endif

@if (Request::is('controller/action'))
    <!-- code block here -->
@endif

Getting Request , Response & ServletContext in the Grails service class

import org.codehaus.groovy.grails.web.util.WebUtils;

Getting current request object:
def request = WebUtils.retrieveGrailsWebRequest().getCurrentRequest();

Getting response object:
def response = WebUtils.retrieveGrailsWebRequest().getCurrentResponse();

Getting servletContext object:
def servletContext = WebUtils.retrieveGrailsWebRequest().getServletContext();